- Edited
xRegnarokx Think about whether you really need stacking of 3d cells. Imo this could better be handled by using only a single floor of gridmap with different cell elevations. You don't need an actual 3d grid.
Moving in a grid, better method?
- Edited
xRegnarokx Here's a demo:
You can toggle between smooth and instant movement via flag in the character node. It's 60 lines of code total. Dummy rules of movement are that cells can be traversed if the elevation difference is 1 or 0.
grid-movement.zip
9kB
xyz Thanks so much for that demo! That looks a lot like what I'd like to eventually accomplish.
Question about the single floor with different cell elevations. Do you mean having blocks that are 1,1,1 and 1,2,1? So rather than stacking a block of height 1 to create an elevation difference you'd just use a block that has a height of 2?
Or are you thinking this would be implemented in another way?
I just don't know how that would look if you have a map with large elevation changes. Or would you just create another gridmap for the new elevation?
Or are you talking more on the data implementation side? To not worry about storing info for stacked cells, but just store the top most cell with a height value? That way you could use Vector2i coords and then just check height?
- Edited
xRegnarokx Question about the single floor with different cell elevations. Do you mean having blocks that are 1,1,1 and 1,2,1? So rather than stacking a block of height 1 to create an elevation difference you'd just use a block that has a height of 2?
You can do it in various ways depending on the actual content and rules in your game, but it's all similar in respect to elevation data storage. You always only need the topmost elevation (if stuff is always stacked). Whether you stack all inside a single mesh or use several gridmap floors, makes no difference really. I used what you described here as it it requires the least code and the simplest setup.
Study that demo. It should clarify things a bit.
xyz So, here is what I've wrote, I tried to make it before then looking at your demo code so, I wouldn't be tempted to imitate it first. I noticed that your code seemed like it would just grab the top tile, regardless if there was a tile directly under it. So, what I tried to do was write something that would sort the top tiles, and also find if there were any tiles that were underneath with a gap between them.
I am still trying to make it fully accurate, it will get me the tiles that I want, but also there are certain cases where another tiles slips by that isn't actually not in the stack.
I'll keep working on it tomorrow, but thought I'd post it here.
extends GridMap
class CellData:
var height: int
var has_below: bool
var is_below: CellData
func _init(iheight: int, ihas_below: bool, iis_below: CellData) -> void:
height = iheight
has_below = ihas_below
is_below = iis_below
var map_cells: Dictionary
func _ready() -> void:
_get_map_cells()
func _get_map_cells() -> void:
var sort_cells: Array[Array] = _sort_cells()
for primary in sort_cells[0]:
var add: = Vector2i(primary.x,primary.z)
for secondary in sort_cells[1]:
if not primary.x == secondary.x:
continue
if not primary.z == secondary.z:
continue
map_cells[add] = CellData.new(primary.y,true,CellData.new(secondary.y,false,null))
if not map_cells.get(add):
map_cells[add] = CellData.new(primary.y,false,null)
for cell in map_cells:
if map_cells[cell].has_below:
print(map_cells[cell].is_below.height,map_cells[cell].height)
func _sort_cells() -> Array[Array]:
var used_cells = get_used_cells()
var sorted: Array[Vector3i]
var below: Array[Vector3i]
#finds the top tiles of the gridmap, and potential tiles below others
for first_cell in used_cells:
var cell_test: Vector3i = first_cell
for second_cell in used_cells:
if first_cell == second_cell:
continue
if not first_cell.x == second_cell.x:
continue
if not first_cell.z == second_cell.z:
continue
if not first_cell.y < second_cell.y:
continue
if abs(first_cell.y - second_cell.y) > 1:
if not below.has(first_cell):
below.append(first_cell)
cell_test = second_cell
if not sorted.has(cell_test):
sorted.append(cell_test)
#finds only the cells in the below array that is below another tile, and not stacked
for cell2 in below:
var cell_below: = Vector3i.ZERO
for cell1 in sorted:
if not cell1.x == cell2.x:
continue
if not cell1.z == cell2.z:
continue
if not abs(cell1.y - cell2.y) > 1:
continue
cell_below = cell2
if cell_below:
below.pop_at(below.find(cell_below))
print(sorted,below)
return [sorted,below]- Edited
xRegnarokx No, I just used a single floor gridmap with hardcoded elevation.
Make the simplest version first. Then upgrade and add finesse and complexity.
In general, your code looks too complicated. It's also too deeply nested.
Take a look at the demo to see how simple this actually can be. I just updated it with even simpler version, so download it again if you already did so previously. It's 15 lines of gridmap code and 35 lines of character code. That's all.
- Edited
xRegnarokx Oh, and if you want to get all top cells, it can also be done in a much simpler way. Simply iterate through all used cells and maintain a dictionary whose key is xz cell coordinate. Whenever you encounter the same xz coordinate, compare its y with the y in the dictionary and overwrite the value if the y is larger than what's already stored. At the end of iteration your dictionary values will be top cells:
func _get_top_cells() -> Array:
var top_cells: Dictionary
for c in get_used_cells():
var c_xz = Vector2i(c.x, c.z)
if not top_cells.has(c_xz) or c.y > top_cells[c_xz].y:
top_cells[c_xz] = c
return top_cells.values() This can also be easily extended to find whole stacks. Just store all cells with same xz in an array under the xz key and in the end sort each of those arrays by y:
func _get_stacks() -> Dictionary:
var stacks: Dictionary
for c in get_used_cells():
var c_xz = Vector2i(c.x, c.z)
if not stacks.has(c_xz):
stacks[c_xz] = []
stacks[c_xz].push_back(c)
for s in stacks.values():
s.sort_custom(func(a, b): return a.y < b.y)
return stacksxyz Okay, I'll redownload the demo. Also, I'll work on implementing a more basic system, and as I develop and run into needs will tweak it.
- Edited
xyz So, I messed around with what you suggested with your most recent code. I got it working very simply, where it would return a dictionary of all the top most cells, so then I sought to tweak it and make it return the top most cells as long as they didn't have a block directly on top of them.
Example a tower of 4 blocks, that was every other cell would return a dictionary of 4 coords at the same xz. However, it would be accessed by the xz coords and then they would be sorted by another dictionary holding their elevations.
Here is the code, it is quite rough, and I am sure not up to snuff.
extends GridMap
var map_cells: Dictionary
func _ready() -> void:
map_cells = _get_top_cells()
func _get_top_cells() -> Dictionary:
var top_cells: Dictionary
for cells in get_used_cells():
var cell_coords: = Vector2i(cells.x,cells.z)
if not top_cells.has(cell_coords):
top_cells[cell_coords] = []
top_cells[cell_coords].push_back(cells)
for x in top_cells.values():
x.sort_custom(func(a,b): return a.y > b.y)
return _get_moveable_cells(top_cells.values())
func _get_moveable_cells(stack: Array) -> Dictionary:
var new_stack: Dictionary
for grp in stack:
var c: Vector3i = grp[0]
if grp.size() == 1:
new_stack[Vector2i(c.x,c.z)] = {c.y:c}
continue
if grp.size() == 2:
if abs(c.y - grp[1].y) >= 2:
new_stack[Vector2i(c.x,c.z)] = {c.y:c,grp[1].y:grp[1]}
continue
new_stack[Vector2i(c.x,c.z)] = {c.y:c}
continue
if grp.size() > 2:
new_stack[Vector2i(c.x,c.z)] = _sort_elevation(grp)
return new_stack
func _sort_elevation(grp: Array) -> Dictionary:
var sorted: Dictionary
var under: bool
for c in grp:
if grp.find(c) + 1 == grp.size():
return sorted
if abs(c.y - grp[grp.find(c) + 1].y) > 1:
if under:
under = false
sorted[grp[grp.find(c) + 1].y] = grp[grp.find(c) + 1]
continue
sorted.merge({c.y:c,grp[grp.find(c) + 1].y:grp[grp.find(c) + 1]})
print(sorted)
continue
if sorted.get(c.y + 1):
continue
sorted[c.y] = c
under = true
return sortedI am also going to do some research on how to better search/compare elements in an array, maybe I should more of pop elements out of a stack or something of the sort to search elements.
Edit: I wonder if I could do something like this with slice as well? It isn't finished but I need to go to bed.
func _sort_elevation(grp: Array) -> Dictionary:
var sorted_dict: Dictionary
var sorted: Array
var first:bool = true
for x in grp.size() - 1:
var slice = grp.slice(0,2)
if first:
if abs(slice.front().y - slice.back().y) > 1:
sorted.append(slice.back())
sorted.append(grp.pop_front())
first = false
continue
if abs(slice.front().y - slice.back().y) > 1:
sorted.append(slice.back())
grp.pop_front()
return {}- Edited
xRegnarokx Again, way too much code. You could have just used my function that gets stacks. Since stacks are sorted by y, simply check if two last y coords in a stack are not adjacent or there's only one cell in a stack. If either is the case, you have a top cell with nothing underneath it:
func _get_floating_top_cells() -> Array:
var stacks = _get_stacks().values()
stacks = stacks.filter( func(s): return s.size() == 1 or abs(s[-1].y - s[-2].y) > 1 )
return stacks.map( func(s): return s[-1] )- Edited
xRegnarokx Oh, just realized you wanted all occupied cells that have space above them. Well that's even simpler. Iterate through all used cells and just check if the cell above is occupied:
func _get_platform_cells() -> Array:
var platform_cells = []
for c in get_used_cells():
if get_cell_item(Vector3i(c.x, c.y + 1, c.z)) == -1:
platform_cells.push_back(c)
return platform_cellsThose could also easily be grouped in a dictionary with xz as a key. It's 2 additional lines of code.
EDIT: Why do all of this though? In a 2.5D game like this there should be no holes in stacks. So simply throw an exception if a hole is found. And display a message that the map is not designed according to rules 
xyz Ahh that is right, you could just check if the cell above returns -1 and this is empty... duh...
Well as far as why to do this, in my game eventually I want to have bridges and such or platforms that are above that you can walk under (like there are in Tibia). In 2D there are no actual gaps it's just rendering order.
However, for 3D in 2.5D I assumed this was the best way to do that.
- Edited
xRegnarokx You're again trying to make a complex system before you made a simple system.
- Edited
xRegnarokx Here's a version of demo that can have holes. All tiles are now same sized cubes. It can handle any number of "bridges" one on top of another.
This is 15 additional lines of code compared to previous version. 60 lines in total in the whole project.
grid-movement2.zip
8kB
- Edited
xyz Cool, thanks, I'll try and implement just that movement. Then I'll slowly add things to it such as other units moving, and detecting/setting occupation of tiles, ect... Thank you so much!
Edit: So, using your code I created a simple movement, and am working with it to understand it better. I did tweak it, and am planning on implementing obstacles to test it out, here is my occupied changing that I added.
func update_occupied(from: Vector2i,to: Vector2i,from_elevation: int, to_elevation: int) -> void:
for cf in map_data[from]:
if not cf.elevation == from_elevation:
continue
cf.occupied = false
for ct in map_data[to]:
if not ct.elevation == to_elevation:
continue
ct.occupied = true- Edited
xRegnarokx Remember that the most important thing is figuring out the best fitting data structure(s) for the problem you want to solve. Doing so can simplify/shorten your code by the order of magnitude. Conversely, choosing inappropriate structure(s) can turn your code into a mess.
Time to yet again inject that timeless Fred Brooks piece of wisdom:
xRegnarokx Cool, thanks, I'll try and implement just that movement. Then I'll slowly add things to it such as other units moving, and detecting/setting occupation of tiles, ect... Thank you so much!
Note that adding other moving units to a system like this is trivial because movement only happens in respect to map data, and is instant. Only the visual representation shows (fake) gradual transition. So when you need to move the unit to some cell, just check if no other unit has its map position at that cell. If that's true, you can safely move it there.
- Edited
- Best Answerset by xRegnarokx
xRegnarokx For completeness, here's the version with the player and arbitrary number of npcs, all moving and respecting cell occupancy of each other. As I already mentioned, this is trivial to add if you store your map/cell data in a proper structure.
We're now at 90 lines of code in total.
gridmap - 20 LOC
character base class - 50 LOC
player - 10 LOC
npc - 10 LOC
grid-movement3.zip
9kB
xyz You definitely make it look easy haha, I have a long way to go to learn how to think through implementation and such.
xRegnarokx Just keep at it. You'll get there.