Get the top value of a dice

fabianom

Hello guys,
I'm trying to get the value of the top face of a dice (3d cube) after rolling it, but I have no idea how to do that.
The dice is a regular 3D mesh and I'm using the following code to get a randon roll:
var arr:Array = [0, 90, 180, 270, 360] rotation_degrees = Vector3(arr.pick_random(), arr.pick_random(), arr.pick_random())

How can I figure out the top face value?

xyz

fabianom Each side of the cube has a normal vector that's either one of 3 orthonormal basis vectors or one of their 3 inverse vectors. So each of those 6 vectors has a die number associated with it (depending on your initial orientation). Take those 6 vectors in global space (from global_transform.basis), find the one that has the largest y component (meaning it's facing the most "up"). The die number associated with that vector is the number on the up facing side of the die.

fabianom

xyz Thanks for the help. I was not able to apply the solution you wrote, but I got it using a raycast for each side of the dice, then, getting the dice top side value from there (the opposite face of the raycast that is colliding is the value I want to get).
Not so beautiful, but it works!

xyz

fabianom Yeah, a bit complicated setup.
Here's the implementation of what I was talking about. No additional nodes needed, everything is calculated from the cube node itself:

func get_top_die_number(die):
	var b = die.global_transform.basis.orthonormalized();
	var axis = [ [b.x, 6], [-b.x, 1], [b.y, 2], [-b.y, 5], [b.z, 4], [-b.z, 3] ]
	axis.sort_custom(func(v1, v2): return v1[0].y > v2[0].y)
	return(axis[0][1])

fabianom

xyz it works! thank you! 🙂

fabianom

Oh I see. I will try your code. Thank you.