Comparing two Binary values with wildcards

Tybobobo

I am trying to figure out a way to check two binary variables and return true if it matches an "binary rule". The binary rule is "00000#1#" where 0 must be 0, 1 must be 1, but # can be either. If I get input "00000111" it should return true. If I get input "00010010" it should return false, as it does not match the 0 must be 0 rule. A hack would be to manually type in all the # values and instead of comparing to the "binary rule", I just check for exact matches - but I figure I should ask if anyone here know how I may solve this more intelligently  <img alt="" height="20">

Tybobobo

I have been unable to find any conversion between decimal and binary values, so I figure I might post this. This script will convert binary to decimal, and decimal to binary. (32 bits)[code]# Converts a decimal value to a binary value and returns itfunc get_binary_from_decimal(var decimal_value): var binary_string = "" var temp var count = 31 # Checking up to 32 bits while(count >= 0): temp = decimal_value >> count if(temp & 1): binary_string = binary_string + "1" else: binary_string = binary_string + "0" count -= 1 # Return the binary value as an int return int(binary_string)# Converts a binary value to a decimal value and returns itfunc get_decimal_from_binary(var binary_value): var decimal_value = 0 var count = 0 var temp while(binary_value != 0): temp = binary_value % 10 binary_value /= 10 decimal_value += temp * pow(2, count) count += 1 # Return decimal value return decimal_value[/code]Posting it here, as I am sure there are ways to improve it - or if someone else just need a quick solution for binary conversion :)

Tybobobo

[b]Solved![/b]And it was easier than I thought.Now in order to do this, I had to use [u]decimals [/u]and compare using a bitwise operator & (something I have been trying for a long time using pure binary values stored in int).So if I wanted to check if we have the 1 in "00010000" in another binary value such as "10110000" I had to convert it into decimals (script above)and do the following:if(another_value & 16):    # there is a 1 in the 000[1]0000 slot; we can now do stuffIt will basically return false if there is no 1 in that 1's slot, as it only returns true if BOTH values contain a 1 at that spot :) Since we don't care about the other values around it; that is okay.It took a long time to figure out because I was only using binary values; and for some reason checking two integers with binary values wont always be correct (false positives on certain values).